If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2-14=-5x-10
We move all terms to the left:
6x^2-14-(-5x-10)=0
We get rid of parentheses
6x^2+5x+10-14=0
We add all the numbers together, and all the variables
6x^2+5x-4=0
a = 6; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·6·(-4)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-11}{2*6}=\frac{-16}{12} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+11}{2*6}=\frac{6}{12} =1/2 $
| 4(10r)=84 | | (x-11)=(2x+8) | | 4j−j=13 | | 6x+26=8x | | -5x-6(x+4)=0 | | 6×3=(b×5)–(b×2) | | 4^-3n=16 | | 6×3=(a×5)–(a×2) | | r=5r-10 | | 22/6x4= | | 1/2x+1/3x=6/7 | | (x-13)=(x+5) | | 2/(3x-1)+(3/(3x+1)=5/3x | | 13(6r+12)=2r+12 | | 3j−4j=13 | | 4j−3j=13 | | 4y-3-2y=9 | | (P-7)(p+10)=0 | | 15(10r+20)=2r+10 | | 5u+12=92 | | N^2-1=-1+7n | | 4/7+2/7x=4 | | 9r^2-1=125 | | 3y+1+2y=26 | | (X-3)(x+4)=-^2+4 | | n-81/8=124/5 | | 4x−9x−5=0 | | (x+5)=(x-13) | | 38x+5=2(21x-2) | | 2x^2−9x−5=0 | | -10-n^2=-108 | | 2(7x+1)=(3x-1) |